How to solve 5((8)/(12))-2y=2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5((8)/(12))-2y=2 | Equatix

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Question

$$5( \frac{ 8 }{ 12 } )-2y=2$$

Solve for y

$y=\frac{2}{3}\approx 0.666666667$

Steps for Solving Linear Equation

Reduce the fraction $\frac{8}{12}$ to lowest terms by extracting and canceling out $4$.

$$5\times \frac{2}{3}-2y=2$$

Express $5\times \frac{2}{3}$ as a single fraction.

$$\frac{5\times 2}{3}-2y=2$$

Multiply $5$ and $2$ to get $10$.

$$\frac{10}{3}-2y=2$$

Subtract $\frac{10}{3}$ from both sides.

$$-2y=2-\frac{10}{3}$$

Convert $2$ to fraction $\frac{6}{3}$.

$$-2y=\frac{6}{3}-\frac{10}{3}$$

Since $\frac{6}{3}$ and $\frac{10}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$-2y=\frac{6-10}{3}$$

Subtract $10$ from $6$ to get $-4$.

$$-2y=-\frac{4}{3}$$

Divide both sides by $-2$.

$$y=\frac{-\frac{4}{3}}{-2}$$

Express $\frac{-\frac{4}{3}}{-2}$ as a single fraction.

$$y=\frac{-4}{3\left(-2\right)}$$

Multiply $3$ and $-2$ to get $-6$.

$$y=\frac{-4}{-6}$$

Reduce the fraction $\frac{-4}{-6}$ to lowest terms by extracting and canceling out $-2$.

$$y=\frac{2}{3}$$

Show Solution