How to solve 5(x-3)-(x+1)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5(x-3)-(x+1) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5(x-3)-(x+1)$$

Evaluate

$4\left(x-4\right)$

Solution Steps

Use the distributive property to multiply $5$ by $x-3$.

$$5x-15-\left(x+1\right)$$

To find the opposite of $x+1$, find the opposite of each term.

$$5x-15-x-1$$

Combine $5x$ and $-x$ to get $4x$.

$$4x-15-1$$

Subtract $1$ from $-15$ to get $-16$.

$$4x-16$$

Show Solution

Expand

$4x-16$

Solution Steps

Use the distributive property to multiply $5$ by $x-3$.

$$5x-15-\left(x+1\right)$$

To find the opposite of $x+1$, find the opposite of each term.

$$5x-15-x-1$$

Combine $5x$ and $-x$ to get $4x$.

$$4x-15-1$$

Subtract $1$ from $-15$ to get $-16$.

$$4x-16$$

Show Solution

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Question

Evaluate

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Solution Steps