How to solve 5(x-3)+2x < 4x+3

Q: How to solve 5(x-3)+2x < 4x+3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5(x-3)+2x < 4x+3 | Equatix

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Question

$$5(x-3)+2x < 4x+3$$

Solve for x

$x<6$

Solution Steps

Use the distributive property to multiply $5$ by $x-3$.

$$5x-15+2x<4x+3$$

Combine $5x$ and $2x$ to get $7x$.

$$7x-15<4x+3$$

Subtract $4x$ from both sides.

$$7x-15-4x<3$$

Combine $7x$ and $-4x$ to get $3x$.

$$3x-15<3$$

Add $15$ to both sides.

$$3x<3+15$$

Add $3$ and $15$ to get $18$.

$$3x<18$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x<\frac{18}{3}$$

Divide $18$ by $3$ to get $6$.

$$x<6$$

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