Solve 5(x+7)+7(x-7)+8(x-4)=48 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5(x+7)+7(x-7)+8(x-4)=48$$

Solve for x

$x = \frac{47}{10} = 4\frac{7}{10} = 4.7$

Steps for Solving Linear Equation

Use the distributive property to multiply $5$ by $x+7$.

$$5x+35+7\left(x-7\right)+8\left(x-4\right)=48$$

Use the distributive property to multiply $7$ by $x-7$.

$$5x+35+7x-49+8\left(x-4\right)=48$$

Combine $5x$ and $7x$ to get $12x$.

$$12x+35-49+8\left(x-4\right)=48$$

Subtract $49$ from $35$ to get $-14$.

$$12x-14+8\left(x-4\right)=48$$

Use the distributive property to multiply $8$ by $x-4$.

$$12x-14+8x-32=48$$

Combine $12x$ and $8x$ to get $20x$.

$$20x-14-32=48$$

Subtract $32$ from $-14$ to get $-46$.

$$20x-46=48$$

Add $46$ to both sides.

$$20x=48+46$$

Add $48$ and $46$ to get $94$.

$$20x=94$$

Divide both sides by $20$.

$$x=\frac{94}{20}$$

Reduce the fraction $\frac{94}{20}$ to lowest terms by extracting and canceling out $2$.

$$x=\frac{47}{10}$$