How to solve 5+1+3+2+1+12+2+6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5+1+3+2+1+12+2+6 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$5+1+3+2+1+12+2+6$$

Evaluate

$32$

Solution Steps

Add $5$ and $1$ to get $6$.

$$6+3+2+1+12+2+6$$

Add $6$ and $3$ to get $9$.

$$9+2+1+12+2+6$$

Add $9$ and $2$ to get $11$.

$$11+1+12+2+6$$

Add $11$ and $1$ to get $12$.

$$12+12+2+6$$

Add $12$ and $12$ to get $24$.

$$24+2+6$$

Add $24$ and $2$ to get $26$.

$$26+6$$

Add $26$ and $6$ to get $32$.

$$32$$

Show Solution

Factor

$2^{5}$

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