Solve 5 + 3x + 10 + 14 + 20 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5+3x+10+14+20$$

Evaluate

$3x+49$

Solution Steps

Add $5$ and $10$ to get $15$.

$$15+3x+14+20$$

Add $15$ and $14$ to get $29$.

$$29+3x+20$$

Add $29$ and $20$ to get $49$.

$$49+3x$$

Differentiate w.r.t. x

$3$

Steps Using Derivative Rule for Sum

Add $5$ and $10$ to get $15$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(15+3x+14+20)$$

Add $15$ and $14$ to get $29$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(29+3x+20)$$

Add $29$ and $20$ to get $49$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(49+3x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$3x^{1-1}$$

Subtract $1$ from $1$.

$$3x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$3\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$3$$