How to solve 5+(-0.6)+(-4)^(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5+(-0.6)+(-4)^(2) | Equatix

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3(r+2s)=2t-4

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Question

$$5+(-0.6)+ { -4 }^{ 2 }$$

Evaluate

$20.4$

Solution Steps

Subtract $0.6$ from $5$ to get $4.4$.

$$4.4+\left(-4\right)^{2}$$

Calculate $-4$ to the power of $2$ and get $16$.

$$4.4+16$$

Add $4.4$ and $16$ to get $20.4$.

$$20.4$$

Show Solution

Factor

$\frac{2 \cdot 3 \cdot 17}{5} = 20\frac{2}{5} = 20.4$

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