Question

$$5+ \sqrt{ 3 } /7-4 \sqrt{ 3 } =47x+3y$$

Solve for x

$x=-\frac{3y}{47}-\frac{27\sqrt{3}}{329}+\frac{5}{47}$

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Solve for y

$y=-\frac{47x}{3}-\frac{9\sqrt{3}}{7}+\frac{5}{3}$

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