Solve 5 + t = 17; 3s - 8t = 18 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5+t=17; 3s-8t=18$$

Solve for t, s

$t=12$
$s=38$

Solution Steps

Consider the first equation. Subtract $5$ from both sides.

$$t=17-5$$

Subtract $5$ from $17$ to get $12$.

$$t=12$$

Consider the second equation. Insert the known values of variables into the equation.

$$3s-8\times 12=18$$

Multiply $-8$ and $12$ to get $-96$.

$$3s-96=18$$

Add $96$ to both sides.

$$3s=18+96$$

Add $18$ and $96$ to get $114$.

$$3s=114$$

Divide both sides by $3$.

$$s=\frac{114}{3}$$

Divide $114$ by $3$ to get $38$.

$$s=38$$

The system is now solved.

$$t=12$$ $$s=38$$