Question

$$5+\underline{5-}; (6-10)=$$

Answer

$$5+5*e^2*IM*u*n^2*d*r*l-;-4$$

Solution


Simplify  \(6-10\)  to  \(-4\).
\[\begin{aligned}&5+underl\imath ne\times 5-\\&-4\end{aligned}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&5+u{n}^{2}d{e}^{2}rl\imath \times 5-\\&-4\end{aligned}\]
Regroup terms.
\[\begin{aligned}&5+5{e}^{2}\imath u{n}^{2}drl-\\&-4\end{aligned}\]