$$[5^{0}+4^{-1}]x]^{2}$$
$\frac{5x}{4}$
$$\left(1+4^{-1}\right)x$$
$$\left(1+\frac{1}{4}\right)x$$
$$\frac{5}{4}x$$
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$\frac{5}{4} = 1\frac{1}{4} = 1.25$
$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(1+4^{-1}\right)x)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(1+\frac{1}{4}\right)x)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5}{4}x)$$
$$\frac{5}{4}x^{1-1}$$
$$\frac{5}{4}x^{0}$$
$$\frac{5}{4}\times 1$$
$$\frac{5}{4}$$
