Question

$$5 \sqrt{ \frac{ 1 }{ 25 } -3 \sqrt{ \frac{ 1 }{ 9 } } }$$

Answer

2*sqrt(6)*IM

Solution


Simplify  \(\sqrt{\frac{1}{9}}\)  to  \(\frac{\sqrt{1}}{\sqrt{9}}\).
\[5\sqrt{\frac{1}{25}-3\times \frac{\sqrt{1}}{\sqrt{9}}}\]
Simplify  \(\sqrt{1}\)  to  \(1\).
\[5\sqrt{\frac{1}{25}-3\times \frac{1}{\sqrt{9}}}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[5\sqrt{\frac{1}{25}-3\times \frac{1}{3}}\]
Cancel \(3\).
\[5\sqrt{\frac{1}{25}-1}\]
Simplify  \(\frac{1}{25}-1\)  to  \(-\frac{24}{25}\).
\[5\sqrt{-\frac{24}{25}}\]
Simplify  \(\sqrt{-\frac{24}{25}}\)  to  \(\sqrt{\frac{24}{25}}\imath \).
\[5\sqrt{\frac{24}{25}}\imath \]
Simplify  \(\sqrt{\frac{24}{25}}\)  to  \(\frac{\sqrt{24}}{\sqrt{25}}\).
\[5\times \frac{\sqrt{24}}{\sqrt{25}}\imath \]
Simplify  \(\sqrt{24}\)  to  \(2\sqrt{6}\).
\[5\times \frac{2\sqrt{6}}{\sqrt{25}}\imath \]
Since \(5\times 5=25\), the square root of \(25\) is \(5\).
\[5\times \frac{2\sqrt{6}}{5}\imath \]
Cancel \(5\).
\[2\sqrt{6}\imath \]