1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 50x140 | Equatix

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Question

$$50x140$$

Evaluate

$50x_{140}$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}50\\\underline{\times\phantom{9}140}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 50 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}50\\\underline{\times\phantom{9}140}\\\phantom{\times9999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 50 with 4. Write the result 200 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}50\\\underline{\times\phantom{9}140}\\\phantom{\times9999}0\\\phantom{\times}200\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 50 with 1. Write the result 50 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}50\\\underline{\times\phantom{9}140}\\\phantom{\times9999}0\\\phantom{\times}200\phantom{9}\\\underline{\phantom{\times}50\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}50\\\underline{\times\phantom{9}140}\\\phantom{\times9999}0\\\phantom{\times}200\phantom{9}\\\underline{\phantom{\times}50\phantom{99}}\\\phantom{\times}7000\end{array}$$

Show Solution

Differentiate w.r.t. x_140

$50$

Steps Using Definition of a Derivative

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$50x_{140}^{1-1}$$

Subtract $1$ from $1$.

$$50x_{140}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$50\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$50$$