How to solve 51/2+21/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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$$51/2+21/5$$

$\frac{297}{10}=29.7$

Least common multiple of $2$ and $5$ is $10$. Convert $\frac{51}{2}$ and $\frac{21}{5}$ to fractions with denominator $10$.

$$\frac{255}{10}+\frac{42}{10}$$

Since $\frac{255}{10}$ and $\frac{42}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{255+42}{10}$$

Add $255$ and $42$ to get $297$.

$$\frac{297}{10}$$

$\frac{3 ^ {3} \cdot 11}{2 \cdot 5} = 29\frac{7}{10} = 29.7$