How to solve 53/60-8(1)/(3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 53/60-8(1)/(3) | Equatix

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$$53/60-8 \frac{ 1 }{ 3 }$$

$-\frac{149}{20}=-7.45$

Multiply $8$ and $3$ to get $24$.

$$\frac{53}{60}-\frac{24+1}{3}$$

Add $24$ and $1$ to get $25$.

$$\frac{53}{60}-\frac{25}{3}$$

Least common multiple of $60$ and $3$ is $60$. Convert $\frac{53}{60}$ and $\frac{25}{3}$ to fractions with denominator $60$.

$$\frac{53}{60}-\frac{500}{60}$$

Since $\frac{53}{60}$ and $\frac{500}{60}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{53-500}{60}$$

Subtract $500$ from $53$ to get $-447$.

$$\frac{-447}{60}$$

Reduce the fraction $\frac{-447}{60}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{149}{20}$$

$-\frac{149}{20} = -7\frac{9}{20} = -7.45$