How to solve 561 imes49

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 561\times49 | Equatix

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Question

$$561 \times 49$$

Evaluate

$27489$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}561\\\underline{\times\phantom{999}49}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 561 with 9. Write the result 5049 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}561\\\underline{\times\phantom{999}49}\\\phantom{\times9}5049\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 561 with 4. Write the result 2244 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}561\\\underline{\times\phantom{999}49}\\\phantom{\times9}5049\\\underline{\phantom{\times}2244\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}561\\\underline{\times\phantom{999}49}\\\phantom{\times9}5049\\\underline{\phantom{\times}2244\phantom{9}}\\\phantom{\times}27489\end{array}$$

Show Solution

Factor

$3\times 7^{2}\times 11\times 17$