How to solve 561 imes625

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 561\times625 | Equatix

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Question

$$561 \times 625$$

Evaluate

$350625$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}561\\\underline{\times\phantom{999}625}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 561 with 5. Write the result 2805 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}561\\\underline{\times\phantom{999}625}\\\phantom{\times99}2805\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 561 with 2. Write the result 1122 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}561\\\underline{\times\phantom{999}625}\\\phantom{\times99}2805\\\phantom{\times9}1122\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 561 with 6. Write the result 3366 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}561\\\underline{\times\phantom{999}625}\\\phantom{\times99}2805\\\phantom{\times9}1122\phantom{9}\\\underline{\phantom{\times}3366\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}561\\\underline{\times\phantom{999}625}\\\phantom{\times99}2805\\\phantom{\times9}1122\phantom{9}\\\underline{\phantom{\times}3366\phantom{99}}\\\phantom{\times}350625\end{array}$$

Show Solution

Factor

$3\times 5^{4}\times 11\times 17$