How to solve 58 imes61=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 58\times61= | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$58 \times 61=$$

Evaluate

$3538$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}58\\\underline{\times\phantom{99}61}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 58 with 1. Write the result 58 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}58\\\underline{\times\phantom{99}61}\\\phantom{\times99}58\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 58 with 6. Write the result 348 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}58\\\underline{\times\phantom{99}61}\\\phantom{\times99}58\\\underline{\phantom{\times}348\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}58\\\underline{\times\phantom{99}61}\\\phantom{\times99}58\\\underline{\phantom{\times}348\phantom{9}}\\\phantom{\times}3538\end{array}$$

Show Solution

Factor

$2\times 29\times 61$