How to solve 584 imes252

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 584\times252 | Equatix

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Question

$$584 \times 252$$

Evaluate

$147168$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}584\\\underline{\times\phantom{999}252}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 584 with 2. Write the result 1168 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}584\\\underline{\times\phantom{999}252}\\\phantom{\times99}1168\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 584 with 5. Write the result 2920 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}584\\\underline{\times\phantom{999}252}\\\phantom{\times99}1168\\\phantom{\times9}2920\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 584 with 2. Write the result 1168 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}584\\\underline{\times\phantom{999}252}\\\phantom{\times99}1168\\\phantom{\times9}2920\phantom{9}\\\underline{\phantom{\times}1168\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}584\\\underline{\times\phantom{999}252}\\\phantom{\times99}1168\\\phantom{\times9}2920\phantom{9}\\\underline{\phantom{\times}1168\phantom{99}}\\\phantom{\times}147168\end{array}$$

Show Solution

Factor

$2^{5}\times 3^{2}\times 7\times 73$