$$5x-2(2x-7)=2(3x-1) \frac{ 7 }{ 2 }$$
$x = \frac{21}{20} = 1\frac{1}{20} = 1.05$
$$5x-4x+14=2\left(3x-1\right)\times \frac{7}{2}$$
$$x+14=2\left(3x-1\right)\times \frac{7}{2}$$
$$x+14=7\left(3x-1\right)$$
$$x+14=21x-7$$
$$x+14-21x=-7$$
$$-20x+14=-7$$
$$-20x=-7-14$$
$$-20x=-21$$
$$x=\frac{-21}{-20}$$
$$x=\frac{21}{20}$$
Show Solution
Hide Solution