Solve 5x-3+4x-7=-80+3x+10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5x-3+4x-7=-80+3x+10$$

Solve for x

$x=-10$

Steps for Solving Linear Equation

Combine $5x$ and $4x$ to get $9x$.

$$9x-3-7=-80+3x+10$$

Subtract $7$ from $-3$ to get $-10$.

$$9x-10=-80+3x+10$$

Add $-80$ and $10$ to get $-70$.

$$9x-10=-70+3x$$

Subtract $3x$ from both sides.

$$9x-10-3x=-70$$

Combine $9x$ and $-3x$ to get $6x$.

$$6x-10=-70$$

Add $10$ to both sides.

$$6x=-70+10$$

Add $-70$ and $10$ to get $-60$.

$$6x=-60$$

Divide both sides by $6$.

$$x=\frac{-60}{6}$$

Divide $-60$ by $6$ to get $-10$.

$$x=-10$$