How to solve 5x-7 <= 2x(1)/(2)

Q: How to solve 5x-7 <= 2x(1)/(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5x-7 <= 2x(1)/(2) | Equatix

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Question

$$5x-7 \leq 2x \frac{ 1 }{ 2 }$$

Solve for x

$x\leq \frac{7}{4}$

Solution Steps

Cancel out $2$ and $2$.

$$5x-7\leq x$$

Subtract $x$ from both sides.

$$5x-7-x\leq 0$$

Combine $5x$ and $-x$ to get $4x$.

$$4x-7\leq 0$$

Add $7$ to both sides. Anything plus zero gives itself.

$$4x\leq 7$$

Divide both sides by $4$. Since $4$ is positive, the inequality direction remains the same.

$$x\leq \frac{7}{4}$$

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