How to solve 5x-7 <= 2x+1

Q: How to solve 5x-7 <= 2x+1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5x-7 <= 2x+1 | Equatix

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Question

$$5x-7 \leq 2x+1$$

Solve for x

$x\leq \frac{8}{3}$

Solution Steps

Subtract $2x$ from both sides.

$$5x-7-2x\leq 1$$

Combine $5x$ and $-2x$ to get $3x$.

$$3x-7\leq 1$$

Add $7$ to both sides.

$$3x\leq 1+7$$

Add $1$ and $7$ to get $8$.

$$3x\leq 8$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x\leq \frac{8}{3}$$

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