Solve 5x(x+1)+(x+1)^(2)= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5x(x+1)+ { \left(x+1 \right) }^{ 2 } =$$

Evaluate

$\left(x+1\right)\left(6x+1\right)$

Solution Steps

Use the distributive property to multiply $5x$ by $x+1$.

$$5x^{2}+5x+\left(x+1\right)^{2}$$

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(x+1\right)^{2}$.

$$5x^{2}+5x+x^{2}+2x+1$$

Combine $5x^{2}$ and $x^{2}$ to get $6x^{2}$.

$$6x^{2}+5x+2x+1$$

Combine $5x$ and $2x$ to get $7x$.

$$6x^{2}+7x+1$$

Expand

$6x^{2}+7x+1$

Solution Steps

Use the distributive property to multiply $5x$ by $x+1$.

$$5x^{2}+5x+\left(x+1\right)^{2}$$

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(x+1\right)^{2}$.

$$5x^{2}+5x+x^{2}+2x+1$$

Combine $5x^{2}$ and $x^{2}$ to get $6x^{2}$.

$$6x^{2}+5x+2x+1$$

Combine $5x$ and $2x$ to get $7x$.

$$6x^{2}+7x+1$$