How to solve 5x+1 < 6

Q: How to solve 5x+1 < 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5x+1 < 6 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5x+1 < 6$$

Solve for x

$x<1$

Solution Steps

Subtract $1$ from both sides.

$$5x<6-1$$

Subtract $1$ from $6$ to get $5$.

$$5x<5$$

Divide both sides by $5$. Since $5$ is positive, the inequality direction remains the same.

$$x<\frac{5}{5}$$

Divide $5$ by $5$ to get $1$.

$$x<1$$

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