How to solve 5x+4y=35

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5x+4y=35 | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5x+4y=35$$

Solve for x

$x=-\frac{4y}{5}+7$

Steps for Solving Linear Equation

Subtract $4y$ from both sides.

$$5x=35-4y$$

Divide both sides by $5$.

$$\frac{5x}{5}=\frac{35-4y}{5}$$

Dividing by $5$ undoes the multiplication by $5$.

$$x=\frac{35-4y}{5}$$

Divide $35-4y$ by $5$.

$$x=-\frac{4y}{5}+7$$

Show Solution

Solve for y

$y=\frac{35-5x}{4}$

Steps for Solving Linear Equation

Subtract $5x$ from both sides.

$$4y=35-5x$$

Divide both sides by $4$.

$$\frac{4y}{4}=\frac{35-5x}{4}$$

Dividing by $4$ undoes the multiplication by $4$.

$$y=\frac{35-5x}{4}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps for Solving Linear Equation

Solve for y

Steps for Solving Linear Equation