Question

$$6 { t }^{ 3 } -5 { t }^{ 2 } +4t > { 2 }^{ 7 }$$

Answer

t>2.9926277160645

Solution


Simplify  \({2}^{7}\)  to  \(128\).
\[6{t}^{3}-5{t}^{2}+4t>128\]
Move all terms to one side.
\[6{t}^{3}-5{t}^{2}+4t-128>0\]
No root was found algebraically. However, the following root(s) were found by numerical methods.
\[t>2.992628\]