Quadratic polynomial can be factored using the transformation $ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$, where $x_{1}$ and $x_{2}$ are the solutions of the quadratic equation $ax^{2}+bx+c=0$.
$$6x^{2}+3x-1=0$$
All equations of the form $ax^{2}+bx+c=0$ can be solved using the quadratic formula: $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$. The quadratic formula gives two solutions, one when $±$ is addition and one when it is subtraction.
Now solve the equation $x=\frac{-3±\sqrt{33}}{12}$ when $±$ is plus. Add $-3$ to $\sqrt{33}$.
$$x=\frac{\sqrt{33}-3}{12}$$
Divide $-3+\sqrt{33}$ by $12$.
$$x=\frac{\sqrt{33}}{12}-\frac{1}{4}$$
Now solve the equation $x=\frac{-3±\sqrt{33}}{12}$ when $±$ is minus. Subtract $\sqrt{33}$ from $-3$.
$$x=\frac{-\sqrt{33}-3}{12}$$
Divide $-3-\sqrt{33}$ by $12$.
$$x=-\frac{\sqrt{33}}{12}-\frac{1}{4}$$
Factor the original expression using $ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$. Substitute $-\frac{1}{4}+\frac{\sqrt{33}}{12}$ for $x_{1}$ and $-\frac{1}{4}-\frac{\sqrt{33}}{12}$ for $x_{2}$.
