How to solve 6/10-12/6+8/12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6/10-12/6+8/12 | Equatix

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Question

$$6/10-12/6+8/12$$

Evaluate

$-\frac{11}{15}\approx -0.733333333$

Solution Steps

Reduce the fraction $\frac{6}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{3}{5}-\frac{12}{6}+\frac{8}{12}$$

Divide $12$ by $6$ to get $2$.

$$\frac{3}{5}-2+\frac{8}{12}$$

Convert $2$ to fraction $\frac{10}{5}$.

$$\frac{3}{5}-\frac{10}{5}+\frac{8}{12}$$

Since $\frac{3}{5}$ and $\frac{10}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-10}{5}+\frac{8}{12}$$

Subtract $10$ from $3$ to get $-7$.

$$-\frac{7}{5}+\frac{8}{12}$$

Reduce the fraction $\frac{8}{12}$ to lowest terms by extracting and canceling out $4$.

$$-\frac{7}{5}+\frac{2}{3}$$

Least common multiple of $5$ and $3$ is $15$. Convert $-\frac{7}{5}$ and $\frac{2}{3}$ to fractions with denominator $15$.

$$-\frac{21}{15}+\frac{10}{15}$$

Since $-\frac{21}{15}$ and $\frac{10}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{-21+10}{15}$$

Add $-21$ and $10$ to get $-11$.

$$-\frac{11}{15}$$

Show Solution

Factor

$-\frac{11}{15} = -0.7333333333333333$