How to solve 6/36+(-7)/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6/36+(-7)/9 | Equatix

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$$6/36+(-7)/9$$

$-\frac{11}{18}\approx -0.611111111$

Reduce the fraction $\frac{6}{36}$ to lowest terms by extracting and canceling out $6$.

$$\frac{1}{6}+\frac{-7}{9}$$

Fraction $\frac{-7}{9}$ can be rewritten as $-\frac{7}{9}$ by extracting the negative sign.

$$\frac{1}{6}-\frac{7}{9}$$

Least common multiple of $6$ and $9$ is $18$. Convert $\frac{1}{6}$ and $\frac{7}{9}$ to fractions with denominator $18$.

$$\frac{3}{18}-\frac{14}{18}$$

Since $\frac{3}{18}$ and $\frac{14}{18}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-14}{18}$$

Subtract $14$ from $3$ to get $-11$.

$$-\frac{11}{18}$$

$-\frac{11}{18} = -0.6111111111111112$