Question

$$6 \frac { 1 } { 4 } + \frac { 17 } { 12 } + 3 \frac { 7 } { 9 }$$

Evaluate

$\frac{103}{9}\approx 11.444444444$

Show Solution

Factor

$\frac{103}{3 ^ {2}} = 11\frac{4}{9} = 11.444444444444445$