$$6 \frac { 1 } { 4 } + \frac { 17 } { 12 } + 3 \frac { 7 } { 9 }$$
$\frac{103}{9}\approx 11.444444444$
$$\frac{24+1}{4}+\frac{17}{12}+\frac{3\times 9+7}{9}$$
$$\frac{25}{4}+\frac{17}{12}+\frac{3\times 9+7}{9}$$
$$\frac{75}{12}+\frac{17}{12}+\frac{3\times 9+7}{9}$$
$$\frac{75+17}{12}+\frac{3\times 9+7}{9}$$
$$\frac{92}{12}+\frac{3\times 9+7}{9}$$
$$\frac{23}{3}+\frac{3\times 9+7}{9}$$
$$\frac{23}{3}+\frac{27+7}{9}$$
$$\frac{23}{3}+\frac{34}{9}$$
$$\frac{69}{9}+\frac{34}{9}$$
$$\frac{69+34}{9}$$
$$\frac{103}{9}$$
Show Solution
Hide Solution
$\frac{103}{3 ^ {2}} = 11\frac{4}{9} = 11.444444444444445$