$$6\frac{1}{5}-(4\frac{3}{10}-1\frac{1}{2})$$
$\frac{17}{5}=3.4$
$$\frac{30+1}{5}-\left(\frac{4\times 10+3}{10}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{4\times 10+3}{10}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{40+3}{10}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{43}{10}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{43}{10}-\frac{2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{43}{10}-\frac{3}{2}\right)$$
$$\frac{31}{5}-\left(\frac{43}{10}-\frac{15}{10}\right)$$
$$\frac{31}{5}-\frac{43-15}{10}$$
$$\frac{31}{5}-\frac{28}{10}$$
$$\frac{31}{5}-\frac{14}{5}$$
$$\frac{31-14}{5}$$
$$\frac{17}{5}$$
Show Solution
Hide Solution
$\frac{17}{5} = 3\frac{2}{5} = 3.4$
