$$6\frac{1}{5}-(4\frac{3}{16}-1\frac{1}{2})$$
$\frac{281}{80}=3.5125$
$$\frac{30+1}{5}-\left(\frac{4\times 16+3}{16}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{4\times 16+3}{16}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{64+3}{16}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{67}{16}-\frac{1\times 2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{67}{16}-\frac{2+1}{2}\right)$$
$$\frac{31}{5}-\left(\frac{67}{16}-\frac{3}{2}\right)$$
$$\frac{31}{5}-\left(\frac{67}{16}-\frac{24}{16}\right)$$
$$\frac{31}{5}-\frac{67-24}{16}$$
$$\frac{31}{5}-\frac{43}{16}$$
$$\frac{496}{80}-\frac{215}{80}$$
$$\frac{496-215}{80}$$
$$\frac{281}{80}$$
Show Solution
Hide Solution
$\frac{281}{2 ^ {4} \cdot 5} = 3\frac{41}{80} = 3.5125$
