$$6\frac{19}{22}-(4\frac{3}{22}-\frac{17}{22})=$$
$\frac{7}{2}=3.5$
$$\frac{132+19}{22}-\left(\frac{4\times 22+3}{22}-\frac{17}{22}\right)$$
$$\frac{151}{22}-\left(\frac{4\times 22+3}{22}-\frac{17}{22}\right)$$
$$\frac{151}{22}-\left(\frac{88+3}{22}-\frac{17}{22}\right)$$
$$\frac{151}{22}-\left(\frac{91}{22}-\frac{17}{22}\right)$$
$$\frac{151}{22}-\frac{91-17}{22}$$
$$\frac{151}{22}-\frac{74}{22}$$
$$\frac{151-74}{22}$$
$$\frac{77}{22}$$
$$\frac{7}{2}$$
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$\frac{7}{2} = 3\frac{1}{2} = 3.5$
