How to solve 6 +2 +1 10 4 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 +2 +1 10 4 5 | Equatix

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Question

$$6 \frac { 3 } { 10 } + 2 \frac { 3 } { 4 } + 1 \frac { 3 } { 5 }$$

Evaluate

$\frac{213}{20}=10.65$

Solution Steps

Multiply $6$ and $10$ to get $60$.

$$\frac{60+3}{10}+\frac{2\times 4+3}{4}+\frac{1\times 5+3}{5}$$

Add $60$ and $3$ to get $63$.

$$\frac{63}{10}+\frac{2\times 4+3}{4}+\frac{1\times 5+3}{5}$$

Multiply $2$ and $4$ to get $8$.

$$\frac{63}{10}+\frac{8+3}{4}+\frac{1\times 5+3}{5}$$

Add $8$ and $3$ to get $11$.

$$\frac{63}{10}+\frac{11}{4}+\frac{1\times 5+3}{5}$$

Least common multiple of $10$ and $4$ is $20$. Convert $\frac{63}{10}$ and $\frac{11}{4}$ to fractions with denominator $20$.

$$\frac{126}{20}+\frac{55}{20}+\frac{1\times 5+3}{5}$$

Since $\frac{126}{20}$ and $\frac{55}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{126+55}{20}+\frac{1\times 5+3}{5}$$

Add $126$ and $55$ to get $181$.

$$\frac{181}{20}+\frac{1\times 5+3}{5}$$

Multiply $1$ and $5$ to get $5$.

$$\frac{181}{20}+\frac{5+3}{5}$$

Add $5$ and $3$ to get $8$.

$$\frac{181}{20}+\frac{8}{5}$$

Least common multiple of $20$ and $5$ is $20$. Convert $\frac{181}{20}$ and $\frac{8}{5}$ to fractions with denominator $20$.

$$\frac{181}{20}+\frac{32}{20}$$

Since $\frac{181}{20}$ and $\frac{32}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{181+32}{20}$$

Add $181$ and $32$ to get $213$.

$$\frac{213}{20}$$

Show Solution

Factor

$\frac{3 \cdot 71}{2 ^ {2} \cdot 5} = 10\frac{13}{20} = 10.65$