$$6\frac{3}{4}+5\frac{1}{1}$$
$\frac{51}{4}=12.75$
$$\frac{24+3}{4}+\frac{5\times 1+1}{1}$$
$$\frac{27}{4}+\frac{5\times 1+1}{1}$$
$$\frac{27}{4}+\frac{5+1}{1}$$
$$\frac{27}{4}+\frac{6}{1}$$
$$\frac{27}{4}+6$$
$$\frac{27}{4}+\frac{24}{4}$$
$$\frac{27+24}{4}$$
$$\frac{51}{4}$$
Show Solution
Hide Solution
$\frac{3 \cdot 17}{2 ^ {2}} = 12\frac{3}{4} = 12.75$
