How to solve ) 6 7/9 - 21/57

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve ) 6 7/9 - 21/57 | Equatix

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$$6 \frac { 7 } { 9 } - \frac { 21 } { 57 }$$

$\frac{1096}{171}\approx 6.409356725$

Multiply $6$ and $9$ to get $54$.

$$\frac{54+7}{9}-\frac{21}{57}$$

Add $54$ and $7$ to get $61$.

$$\frac{61}{9}-\frac{21}{57}$$

Reduce the fraction $\frac{21}{57}$ to lowest terms by extracting and canceling out $3$.

$$\frac{61}{9}-\frac{7}{19}$$

Least common multiple of $9$ and $19$ is $171$. Convert $\frac{61}{9}$ and $\frac{7}{19}$ to fractions with denominator $171$.

$$\frac{1159}{171}-\frac{63}{171}$$

Since $\frac{1159}{171}$ and $\frac{63}{171}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{1159-63}{171}$$

Subtract $63$ from $1159$ to get $1096$.

$$\frac{1096}{171}$$

$\frac{2 ^ {3} \cdot 137}{3 ^ {2} \cdot 19} = 6\frac{70}{171} = 6.409356725146199$