$$6\frac{8}{4}+9\frac{6}{3}-\frac{6}{3}=$$
$17$
$$\frac{24+8}{4}+\frac{9\times 3+6}{3}-\frac{6}{3}$$
$$\frac{32}{4}+\frac{9\times 3+6}{3}-\frac{6}{3}$$
$$8+\frac{9\times 3+6}{3}-\frac{6}{3}$$
$$8+\frac{27+6}{3}-\frac{6}{3}$$
$$8+\frac{33}{3}-\frac{6}{3}$$
$$8+11-\frac{6}{3}$$
$$19-\frac{6}{3}$$
$$19-2$$
$$17$$
Show Solution
Hide Solution