How to solve 6-2x > x+9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6-2x > x+9 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6-2x > x+9$$

Solve for x

$x<-1$

Solution Steps

Subtract $x$ from both sides.

$$6-2x-x>9$$

Combine $-2x$ and $-x$ to get $-3x$.

$$6-3x>9$$

Subtract $6$ from both sides.

$$-3x>9-6$$

Subtract $6$ from $9$ to get $3$.

$$-3x>3$$

Divide both sides by $-3$. Since $-3$ is negative, the inequality direction is changed.

$$x<\frac{3}{-3}$$

Divide $3$ by $-3$ to get $-1$.

$$x<-1$$

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Question

Solve for x

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