How to solve 6 - b < 8 - 4b

Q: How to solve 6 - b < 8 - 4b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 - b < 8 - 4b | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6-b<8-4b$$

Solve for b

$b<\frac{2}{3}$

Solution Steps

Add $4b$ to both sides.

$$6-b+4b<8$$

Combine $-b$ and $4b$ to get $3b$.

$$6+3b<8$$

Subtract $6$ from both sides.

$$3b<8-6$$

Subtract $6$ from $8$ to get $2$.

$$3b<2$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$b<\frac{2}{3}$$

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Question

Solve for b

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