How to solve 6 - (4a - 3) >= 8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 - (4a - 3) >= 8 | Equatix

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$$6-(4a-3)\ge8$$

$a\leq \frac{1}{4}$

To find the opposite of $4a-3$, find the opposite of each term.

$$6-4a-\left(-3\right)\geq 8$$

The opposite of $-3$ is $3$.

$$6-4a+3\geq 8$$

Add $6$ and $3$ to get $9$.

$$9-4a\geq 8$$

Subtract $9$ from both sides.

$$-4a\geq 8-9$$

Subtract $9$ from $8$ to get $-1$.

$$-4a\geq -1$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$a\leq \frac{-1}{-4}$$

Fraction $\frac{-1}{-4}$ can be simplified to $\frac{1}{4}$ by removing the negative sign from both the numerator and the denominator.

$$a\leq \frac{1}{4}$$