How to solve 6(2 + b) = 3b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6(2 + b) = 3b | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6(2+b)=3b$$

Solve for b

$b=-4$

Steps for Solving Linear Equation

Use the distributive property to multiply $6$ by $2+b$.

$$12+6b=3b$$

Subtract $3b$ from both sides.

$$12+6b-3b=0$$

Combine $6b$ and $-3b$ to get $3b$.

$$12+3b=0$$

Subtract $12$ from both sides. Anything subtracted from zero gives its negation.

$$3b=-12$$

Divide both sides by $3$.

$$b=\frac{-12}{3}$$

Divide $-12$ by $3$ to get $-4$.

$$b=-4$$

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Question

Solve for b

Steps for Solving Linear Equation