Solve 5 ) 6(z - 3) + 2(z + 2) = 10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6 ( z - 3 ) + 2 ( z + 2 ) = 10$$

Solve for z

$z=3$

Steps for Solving Linear Equation

Use the distributive property to multiply $6$ by $z-3$.

$$6z-18+2\left(z+2\right)=10$$

Use the distributive property to multiply $2$ by $z+2$.

$$6z-18+2z+4=10$$

Combine $6z$ and $2z$ to get $8z$.

$$8z-18+4=10$$

Add $-18$ and $4$ to get $-14$.

$$8z-14=10$$

Add $14$ to both sides.

$$8z=10+14$$

Add $10$ and $14$ to get $24$.

$$8z=24$$

Divide both sides by $8$.

$$z=\frac{24}{8}$$

Divide $24$ by $8$ to get $3$.

$$z=3$$