How to solve 6+24/6-8 imes3-2=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6+24/6-8\times3-2= | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$6+24/6-8 \times 3-2=$$

Evaluate

$-16$

Solution Steps

Divide $24$ by $6$ to get $4$.

$$6+4-8\times 3-2$$

Add $6$ and $4$ to get $10$.

$$10-8\times 3-2$$

Multiply $8$ and $3$ to get $24$.

$$10-24-2$$

Subtract $24$ from $10$ to get $-14$.

$$-14-2$$

Subtract $2$ from $-14$ to get $-16$.

$$-16$$

Show Solution

Factor

$-16$

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