Question

$$6+ \sqrt{ 2 \sqrt{ 4 \sqrt{ 6 } } }$$

Answer

$$6+2*6^(1/8)$$

Solution


Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[6+\sqrt{2\sqrt{4}\sqrt{\sqrt{6}}}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[6+\sqrt{2\times 2\sqrt{\sqrt{6}}}\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[6+\sqrt{2\times 2\times {6}^{\frac{1\times 1}{2\times 2}}}\]
Simplify  \(1\times 1\)  to  \(1\).
\[6+\sqrt{2\times 2\sqrt[2\times 2]{6}}\]
Simplify  \(2\times 2\)  to  \(4\).
\[6+\sqrt{4\sqrt[4]{6}}\]
Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[6+\sqrt{4}\sqrt{\sqrt[4]{6}}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[6+2\sqrt{\sqrt[4]{6}}\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[6+2\times {6}^{\frac{1\times 1}{4\times 2}}\]
Simplify  \(1\times 1\)  to  \(1\).
\[6+2\sqrt[4\times 2]{6}\]
Simplify  \(4\times 2\)  to  \(8\).
\[6+2\sqrt[8]{6}\]

Decimal Form: 8.502067