$$6^{2}\div6+4\times(3+1\div1)-9$$
$13$
$$6^{1}+4\left(3+\frac{1}{1}\right)-9$$
$$6^{1}+4\left(3+1\right)-9$$
$$6+4\left(3+1\right)-9$$
$$6+4\times 4-9$$
$$6+16-9$$
$$22-9$$
$$13$$
Show Solution
Hide Solution
