$$6 \times (3 \times (-9+4(5 \times 3-9)-3.(40-8))$$
$-1458$
$$18\left(-9+4\left(5\times 3-9\right)-3\left(40-8\right)\right)$$
$$18\left(-9+4\left(15-9\right)-3\left(40-8\right)\right)$$
$$18\left(-9+4\times 6-3\left(40-8\right)\right)$$
$$18\left(-9+24-3\left(40-8\right)\right)$$
$$18\left(15-3\left(40-8\right)\right)$$
$$18\left(15-3\times 32\right)$$
$$18\left(15-96\right)$$
$$18\left(-81\right)$$
$$-1458$$
Show Solution
Hide Solution