How to solve 60106743 imes4100

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 60106743\times4100 | Equatix

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Question

$$60106743 \times 4100$$

Evaluate

$246437646300$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}60106743\\\underline{\times\phantom{999999}4100}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 60106743 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}60106743\\\underline{\times\phantom{999999}4100}\\\phantom{\times9999999999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 60106743 with 0. Write the result 0 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}60106743\\\underline{\times\phantom{999999}4100}\\\phantom{\times9999999999}0\\\phantom{\times999999999}0\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 60106743 with 1. Write the result 60106743 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}60106743\\\underline{\times\phantom{999999}4100}\\\phantom{\times9999999999}0\\\phantom{\times999999999}0\phantom{9}\\\phantom{\times}60106743\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 60106743 with 4. Write the result 240426972 at the end leaving 3 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{2}\times 3^{2}\times 5^{2}\times 41\times 281\times 23767$