1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6|1/6/9 | Equatix

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Question

$$6|1/6/9$$

$\frac{1}{9}\approx 0.111111111$

Express $\frac{\frac{1}{6}}{9}$ as a single fraction.

$$6|\frac{1}{6\times 9}|$$

Multiply $6$ and $9$ to get $54$.

$$6|\frac{1}{54}|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $\frac{1}{54}$ is $\frac{1}{54}$.

$$6\times \frac{1}{54}$$

Multiply $6$ and $\frac{1}{54}$ to get $\frac{6}{54}$.

$$\frac{6}{54}$$

Reduce the fraction $\frac{6}{54}$ to lowest terms by extracting and canceling out $6$.

$$\frac{1}{9}$$

$\frac{1}{3 ^ {2}} = 0.1111111111111111$