Solve 63/7+(12-8)\times(5\times2)-18+4 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$63/7+(12-8) \times (5 \times 2)-18+4$$

Evaluate

$35$

Solution Steps

Divide $63$ by $7$ to get $9$.

$$9+\left(12-8\right)\times 5\times 2-18+4$$

Subtract $8$ from $12$ to get $4$.

$$9+4\times 5\times 2-18+4$$

Multiply $4$ and $5$ to get $20$.

$$9+20\times 2-18+4$$

Multiply $20$ and $2$ to get $40$.

$$9+40-18+4$$

Add $9$ and $40$ to get $49$.

$$49-18+4$$

Subtract $18$ from $49$ to get $31$.

$$31+4$$

Add $31$ and $4$ to get $35$.

$$35$$

Factor

$5\times 7$